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X^2+X=0.53125
We move all terms to the left:
X^2+X-(0.53125)=0
We add all the numbers together, and all the variables
X^2+X-0.53125=0
a = 1; b = 1; c = -0.53125;
Δ = b2-4ac
Δ = 12-4·1·(-0.53125)
Δ = 3.125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{3.125}}{2*1}=\frac{-1-\sqrt{3.125}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{3.125}}{2*1}=\frac{-1+\sqrt{3.125}}{2} $
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